Another maths problem

Xevrex

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This isn't easy mathematics. I'm very good at math, it's my specialty, and I was just stumped on this one.

As a preface, it's geometry. If anyone came in here expecting algebra, you'll probably be sorely dissapointed.

Anyway, we're "learning" about the tangent ratio in my Geometry Honors class (I say "learning" because I, like others in the class, already know it very well) and we were given problems for homework. I was stumped on this one, as this came from the challenge questions:

Using Tan-1 A (inverse of tangent, of course), find the measure of angle A.

(Tan A) / (1 + Tan A) = 0.5437

I've tried everything to solve for Tan A. I can't figure it out. Help?

EDIT: Nevermind.

For those interested, the answer was angle A = about 50 degrees.
 
"This isn't easy mathematics. I'm very good at math, it's my specialty, and I was just stumped on this one."

Haha cummon thats the easiest problem I've ever seen posted here. How old are you 12?

TanA=0.54(1+tanA)
TanA=0.54+0.54TanA
-.54=1.54tanA
TanA=-.54/1.54

then inverse
 
That's like... year 11, year 12 maths?
 
Thats a pretty simple problem for someone who considers math his specialty :p. No worries we've all been there.
 
Yeah. I was tired, I guess. I didn't even notice how easy it was until I woke up the next morning and took another look at it.

And no, I'm not 12. :p

And you can blame Emporius for not telling me how easy it was either.
 
I took geometry in the summer so I didn't have to arse with it in the regular year. That was like 5.5 years ago...time ****ing flies.
 
Well, your question is already Googlable.
I'm Feeling Lucky

It's a good thing no one revealed how to arrive at the corect answer.

We couldn't have that happen here. :stare:
 
Okay, since the first one was solved, here is a harder one for you calculus lovers.

Solve this differential equation
equation.jpg
 
Not really sure if I did this right. Differential Equations have gone a little cold in my head.

(2x^3-y)dx + (2x^2y+x)dy = 0

2x^3dx + 2x^2ydy + (xdy - ydx) = 0

2xdx + 2ydy + (xdy ? ydx)/x^2 = 0

2xdx +2ydy + d(y/x) = 0

Integrate

x^2 + y^2 + y/x = c

It's most probably complete bullshit.
 
Between line 3 and line 4, things aren't quite right I don't think, and after that you can't treat dy and dx the same when you are integrating with respect to one of them or both of them.
 
Between line 3 and line 4, things aren't quite right I don't think, and after that you can't treat dy and dx the same when you are integrating with respect to one of them or both of them.

Aaaah well I tried. I seriously lack any motivation unless deadlines are involved.
 
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