e^(i*pi) + 1 = 0

Glad I never have to do maths again. BTW, is "i" just any number you can think of?
 
You know, if you write this equation down on paper and put a mirror diagonally across it, take a couple of steps back and squint... you'll see the number '42' appear.
 
I haven't seen "i" since learning about it. Proving it's retarded nature of existance.
/ignorance
 
Pi...what the **** do you think you are doing hiding in that equation??? did you think we wouldn't notice?
 
e_to_the_pi_times_i.png
 
riomhaire said:
No, seeing as it is only made up of 5 known (give or take) constants. But it's pretty crazy.
Click to expand...

The equation itself is just pretty, but the formula which produces it is very useful. It's an engineers tool, and a mathematician's toy.

mindless_moder said:
Electrical Engineers use them all the time to calculate imaginary resistances and powers :) .
Click to expand...

You study electrical engineering?
 
In DC circuits, you can get away with using Ohm's Law: V=IR where V, I and R are all real numbers. When you use AC current (which is like a wave) Ohm's law becomes V=IZ where V, I and Z are all complex numbers (of the form a+ib or r*e^iθ).

Z is based on the components of the circuit. Z for plain resistor is just R, Z for capacitor is 1/iwC (= -i/wc), Z for and inductor is iwL.

If you use Euler's Identity you can easily determine the relationship between V and I. For example, in a circuit with only an inductor and an AC power source:

Z=iwL = wL*e^i(pi/2).
I=I(0)e^iwt

V=IZ = [I(0)e^iwt][wL*e^i(pi/2)]
= I(0)wL*e^i(wt+pi/2)

{as (e^a)*(e^b) = e^(a+b)}

Therefore the voltage leads the current by pi/2.

Alternatively you can use Phasor Diagrams to do the same thing, but the way I just did it is far easier and more direct.

I don't expect you to understand any of this, just know that Euler's Identity definitely does have its uses.
 
Avoidist said:
In DC circuits, you can get away with using Ohm's Law: V=IR where V, I and R are all real numbers. When you use AC current (which is like a wave) Ohm's law becomes V=IZ where V, I and Z are all complex numbers (of the form a+ib or r*e^iθ).

Z is based on the components of the circuit. Z for plain resistor is just R, Z for capacitor is 1/iwC (= -i/wc), Z for and inductor is iwL.

If you use Euler's Identity you can easily determine the relationship between V and I. For example, in a circuit with only an inductor and an AC power source:

Z=iwL = wL*e^i(pi/2).
I=I(0)e^iwt

V=IZ = [I(0)e^iwt][wL*e^i(pi/2)]
= I(0)wL*e^i(wt+pi/2)

{as (e^a)*(e^b) = e^(a+b)}

Therefore the voltage leads the current by pi/2.

Alternatively you can use Phasor Diagrams to do the same thing, but the way I just did it is far easier and more direct.

I don't expect you to understand any of this, just know that Euler's Identity definitely does have its uses.
Click to expand...
300px-John_Cleese.jpg


I have so many questions to ask you.
 
Avoidist said:
In DC circuits, you can get away with using Ohm's Law: V=IR where V, I and R are all real numbers. When you use AC current (which is like a wave) Ohm's law becomes V=IZ where V, I and Z are all complex numbers (of the form a+ib or r*e^iθ).

Z is based on the components of the circuit. Z for plain resistor is just R, Z for capacitor is 1/iwC (= -i/wc), Z for and inductor is iwL.

If you use Euler's Identity you can easily determine the relationship between V and I. For example, in a circuit with only an inductor and an AC power source:

Z=iwL = wL*e^i(pi/2).
I=I(0)e^iwt

V=IZ = [I(0)e^iwt][wL*e^i(pi/2)]
= I(0)wL*e^i(wt+pi/2)

{as (e^a)*(e^b) = e^(a+b)}

Therefore the voltage leads the current by pi/2.

Alternatively you can use Phasor Diagrams to do the same thing, but the way I just did it is far easier and more direct.

I don't expect you to understand any of this, just know that Euler's Identity definitely does have its uses.
Click to expand...
Hah, just what I'm studying. Glad to see I'm not alone.
 
Avoidist said:
In DC circuits, you can get away with using Ohm's Law: V=IR where V, I and R are all real numbers. When you use AC current (which is like a wave) Ohm's law becomes V=IZ where V, I and Z are all complex numbers (of the form a+ib or r*e^iθ).

Z is based on the components of the circuit. Z for plain resistor is just R, Z for capacitor is 1/iwC (= -i/wc), Z for and inductor is iwL.

If you use Euler's Identity you can easily determine the relationship between V and I. For example, in a circuit with only an inductor and an AC power source:

Z=iwL = wL*e^i(pi/2).
I=I(0)e^iwt

V=IZ = [I(0)e^iwt][wL*e^i(pi/2)]
= I(0)wL*e^i(wt+pi/2)

{as (e^a)*(e^b) = e^(a+b)}

Therefore the voltage leads the current by pi/2.

Alternatively you can use Phasor Diagrams to do the same thing, but the way I just did it is far easier and more direct.

I don't expect you to understand any of this, just know that Euler's Identity definitely does have its uses.
Click to expand...

Yes that is all well and good but I know from experience that as soon as you attempt to use any of this for real life, especially with those horrible circuit test boards, it never EVER works. D:

Damn electronics D:
 
maths? thats only for kids in school. :rolling::rolling::rolling:
 
You must log in or register to reply here.

Similar threads

TechnoHippyChic
The Many Diversions of THC's Work Lunches
Replies
3
Views
2K
TechnoHippyChic
TechnoHippyChic
B
Half-Life 2: Episode Two - Cyril, Fred, and friends
Replies
0
Views
5K
Barnz
B
Omnomnick
APRIL FOOLS: Valve Sold To HTC For $4.2B! - ValveTime Spotlight
Replies
6
Views
5K
Clan Wolf 2
Clan Wolf 2
Omnomnick
Valve Partners With Lionsgate To Bring Films To Steam
Replies
1
Views
4K
Lolcomputer
Lolcomputer
bbson john
Hi everyone. I am new to this forum!
Replies
11
Views
6K
Tollbooth Willie
Tollbooth Willie
Back
Top