Math problem...

[Moto]

Hello all. I have a math question that is pretty basic, but it is confusing me and I want to be sure I understand it for my test. If one of the math whizzes here could help me with it, that would be awesome. Here it is:

If H varies inversely as q, and H=0.03 when q=0.01, what is H when q=0.05?

Sorry I've asked for essay help and this. I won't make a habit of it.

 

[PvtRyan]

I don't know what part of math this is, so this is a blind guess from me:

If h varies inversely to q, and q gets 0.04 bigger, doesn't h get 0.04 smaller? So -0.01?

 

[The Monkey]

I thank Jesus every day of my life that I don't have to do that shit no more.

 

[Ennui]

Yeah, same here, I placed out of all my uni math classes and it's goodbye mathematics.

 

[Operational]

Do you know how H varies inversely with q, there are different types of inverse relationships... It might help if you give us the question word for word.

But if I had to take a guess at it:

H = A * 1/q (this line changes depending upon the type of inverse relationship)
_________________
So when q=0.01 and H=0.03

0.03 = A/0.01

A = 0.0003
_________________
Which makes

H = 0.0003/q

so when q = 0.05

H = 0.0003/0.05 = 0.006

 

[DEATH eVADER]

I'm glad this doesn't have any relevance to my line of work

 

[mindless_moder]

bingo ^ you need to express the proportionality with a constant, H being inversely proportional to q means that H = K(some constant)/q if H was directly proportional it would be H = Kq .

 

[soulslicer]

so dam bloddy easy
If H varies inversely as q, and H=0.03 when q=0.01, what is H when q=0.05?

H=k/q
Then 0.03*0.01 = k which is 0.0003
Then 0.05=0.0003/q then you can find out q.

 

[The Monkey]

 

[mindless_moder]

sex = fun ?

 

[Tyguy]

divide by zero