New Physics Problem (yay)

[xcellerate]

A 2.40 kg steel ball strikes a wall with a speed of 10.0 m/s at an angle of 60.0° with the surface. It bounces off with the same speed and angle. If the ball is in contact with the wall for 0.240 s, what is the average force exerted on the ball by the wall?

x-component? (newtons)
y-component? (newtons)

I've got a 9/10 on my homework right now, and this is the last question :angry:

 

[Naudian]

2

 

[dfc05]

For x-component:

velocity toward wall vi = 10sin(60)
velocity away vf = -10sin(60)

dv = vf-vi = -20sin(60)

F = ma = m(dv/dt) = 2.40*(-20sin(60)/0.240)

(it's negative if you take away from the wall to be the - direction. positive if you're finding magnitude, or if away from wall is + direction)

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For y-component:

velocity toward wall = velocity away from wall

so dv = 0 --> F = 0 (wall is just pushing it in the x direction, not in y)