mortiz
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hi, I was wondering if someone could explain to me the following:
I'm doing a past P4 Maths Paper (AQA January 2003) and i've come a cropper on a specific question.
The question asks you to show (3sin2x + cos2x)^2 in the form Asin4x + Bcos4x + C. I've multiplied out the brackets to get 9(sin2x)^2 + (cos2x)^2 + 6sin2xcos2x and replaced 6sin2xcos2x with 3sin4x. The problem was wondering where to go next, after much pondering I decided to look at the Mark Scheme and I saw the following replacements: 9(sin2x)^2 = (9/2)(1-cos4x) and (cos2x)^2 = (1/2)(1 + cos4x) . Needless to say these baffled me even more.
Does someone mind explaining how they got from the left equations in both cases to the right one? It says something about the double angle formulae but I don't see how using that would help get the above replacements.
I'm doing a past P4 Maths Paper (AQA January 2003) and i've come a cropper on a specific question.
The question asks you to show (3sin2x + cos2x)^2 in the form Asin4x + Bcos4x + C. I've multiplied out the brackets to get 9(sin2x)^2 + (cos2x)^2 + 6sin2xcos2x and replaced 6sin2xcos2x with 3sin4x. The problem was wondering where to go next, after much pondering I decided to look at the Mark Scheme and I saw the following replacements: 9(sin2x)^2 = (9/2)(1-cos4x) and (cos2x)^2 = (1/2)(1 + cos4x) . Needless to say these baffled me even more.
Does someone mind explaining how they got from the left equations in both cases to the right one? It says something about the double angle formulae but I don't see how using that would help get the above replacements.