What trigonometric identity is this? (1 - cos^2 x)

MiccyNarc

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As the title says, is that a trig identity or am I missing something here? This keeps coming up and it's driving me insane. Thanks for any help!
EDIT: Nevermind, found it.

One more question, then that means sin^2 x + 1 - cos^2x = sin^2 x + sin^2 x = 2sin^2 x?
Or am I still missing something here. I hate this stuff :(
 
Sounds correct. Looks correct.
Should be correct.

If its not, then I shouldn't be taking a maths class.
 
sin^2 x + 1 - cos^2x = sin^2 x + sin^2 x = 2sin^2 x = Baykuns to the 4th power divided by 27.

I have no idea, you'd get further screaming at a can of peaches than asking me to help you.
 
Look at your notes, if you took any it's all there, or look at your book.
 
300px-Circle-trig6.png


Considering the radius of this circle equals to one, then Pythagoras tells us that
efaa26311781f6e9c04ecd1c6f9f37e9.png


In the circle, each side of a given triangle is given by either cos (x) or sin (x). So we can deduce this equation

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Look at your notes, if you took any it's all there, or look at your book.
The expected smartass response.
No, my teacher did not go through every single possible trig identity, and I've been through all of it in my book, and it's much like finding a needle in a haystack.
 
These identities are crazy useful as soon as you start going into higher-level algebra and calculus.
 
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