Math!! ^_^

You people are f*cking crazy. I can barely manage an A- in pre-calculus.
 
JNightshade said:
You people are f*cking crazy. I can barely manage an A- in pre-calculus.
I've got Math exams in two days D:
 
This one is easy:

x=the sum of all exterior angles of a polygon if each interior angle has one exterior angle

What is x?
 
360?
 
Ikerous said:
I knew that would be too easy...hmmm...

If the ratio of the supplement of an angle to the complement of an angle is 5:2, then what is the measure of the supplement?
 
ricera10 said:
I knew that would be too easy...hmmm...

If the ratio of the supplement of an angle to the complement of an angle is 5:2, then what is the measure of the supplement?

I dont even understand that sentance... I guess I havn't took a high enough math yet. Oh well.

Try this one:

f(6) = .6908733
f(7) = .62179
Y-intercept = 1.3
What is the rate of decay?

Im too tired to do any problems right now, its 12:00 at night for me. Ill come back after I get a good night of sleep.
 
Puzzlemaker said:
I dont even understand that sentance... I guess I havn't took a high enough math yet. Oh well.

Try this one:

f(6) = .6908733
f(7) = .62179
Y-intercept = 1.3
What is the rate of decay?

Im too tired to do any problems right now, its 12:00 at night for me. Ill come back after I get a good night of sleep.
Rate of decay? I think you must be on a higher level math than me.

These are too easy. I'll post geometry problems tomorrow.
 
The_Monkey said:
y=6x-6
y=1-8x

Where do these two lines intersect?

Y = 1-8x is the same as -8x + 1, and that makes it a bit easier to work with...

1.16666666 is the intersecting point. I think.
 
The_Monkey said:
y=6x-6
y=1-8x

Where do these two lines intersect?

Wow, easy one:

Find X:
6x - 6 = 1 - 8x
6x + 8x = 1 + 6
14x = 7
x = 1/2

Find Y:
If x = 1/2,
1 - 8x = y
1 - 8(1/2) = y
1- 4 = y
-3 = y

Answer: Intersection point = (1/2 ; -3)


EDIT: Oops
 
Well, one of us messed up... I think I probobly did... Let me re-do it.

Edit: Yep, I found what I did wrong. Hold on a sec.

Edit2: Yep, x = 1/2, and y = -3. Your right, my bad.
 
Puzzlemaker said:
Well, one of us messed up... I think I probobly did... Let me re-do it.

Edit: Yep, I found what I did wrong. Hold on a sec.

An intersection point is supposed to be two coordinates, for it is 2 dimensions.
 
Here's a problem (translated directly from my french book, mind the syntax):

A real estate society studies the construction project of a new commercial center. To assure its rentability, the average monthly fees of each store must be 75$ per square meter (m²). Two prominent stores have already accepted to rent 10 000 m² each at a special monthly fee of 20$ per square meter (m²). The commercial center anticipates the monthly fees of 100$ per square meters (m²) for every other boutiques.

a) Determinate the mathematical formula of the function which enables us to know the average monthly fees per square meter (m²) for all the stores in the commercial center. It must be in function with the area allowed to the boutiques (in square meter).

b) What must be the area allowed to the boutiques, so as to the commercial center's rentability is accurate?
 
The toughest problem I've ever gotten is this

"There are two numbers x and y such that 1<x<y<100. Two robots S and P are respectively given the sum of the two numbers and the product of the two numbers. Both robots are perfect in every way so that everything they say is true. This is their conversation:

S: You do not know what the two numbers are.
P: Yes I do
S: So do I

What are the two numbers?"

No tricks to it, just simple old logic and math
 
Dan said:
The toughest problem I've ever gotten is this

"There are two numbers x and y such that 1<x<y<100. Two robots S and P are respectively given the sum of the two numbers and the product of the two numbers. Both robots are perfect in every way so that everything they say is true. This is their conversation:

S: You do not know what the two numbers are.
P: Yes I do
S: So do I

What are the two numbers?"

No tricks to it, just simple old logic and math

numbers are 2 and 3?
 
I dont think they are 2 and 3..

are they 1.9999999999999 (Going on infinitally) and 2?

I dont know. Im grasping at straws here. That doesn't make any sence. How can you both not know what the numbers are and know what the numbers are at the same time?
 
sorry, x and y are both integers, and everything that the robots say is true (when they say it). So basically you have to deduce what the mathematical implications are for each statement.
 
Dan said:
sorry, x and y are both integers, and everything that the robots say is true (when they say it). So basically you have to deduce what the mathematical implications are for each statement.

Did I get it? (2 and 3)
 
Dan said:
The toughest problem I've ever gotten is this

"There are two numbers x and y such that 1<x<y<100. Two robots S and P are respectively given the sum of the two numbers and the product of the two numbers. Both robots are perfect in every way so that everything they say is true. This is their conversation:

S: You do not know what the two numbers are.
P: Yes I do
S: So do I

What are the two numbers?"

No tricks to it, just simple old logic and math

The only thing I got was that when S tells P that he/she/it doesn't know what the two numbers are, he is somehow informing P what teh two numbers are. Then when P replies, S is somehow informed what the two numbers are.

Hmm.
 
An unkown mass of glass (c = 0.8372 J/g°C) at 90.0 °C is dropped into a calorimeter (c = 1.23 J/g°C, m = 7.0 g) that contains 75.0 g of water. If the temperature increases from 24.3 °C at the beginning of the experiment to 26.6 °C by the end, what was the mass of the glass?

They didn't give the specific heat of water in the problem so I will. It's (c = 4.184 J/g°C)

My answer came out to be:
13.97069 g
 
yep 13.97 g. The tougher problems like that involve heat of formation as well. For example ice cubs added to cold water to make a ice/water mixture.

As for the problem I posted above, I'll make it a bit easier for you guys. x and y are both less than 20. And the answer involves the use of prime numbers
 
Prime numbers below twenty and above one are:

3, 5, 7, 13, 17, 19.

Im think.

Soo...

Hmm.

I dont know.
 
whooops. Roight. 2 too. I knew that. I was just testing... You... All...

*Ninjavanish*
 
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