Needs mafs halps

sinkoman

sinkoman

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Please please please don't mock me for asking for help in Algebra Two. Math isn't my strong point (yeah, everybody says that), and I can't find any help online with this.

Does (4x^(2/3))/(5x^(1/2)) = 4x^(2/3) * 5x^-(1/2) = 20x^-(1/3)

or...

(4x^(2/3))/(5x^(1/2)) = 4x^(2/3) * 5^-1 * x^-(1/2)
 
4

I'm not very good at math(in fact, I suck) But I'm confident the answer is 4.
 
Raziaar said:
4

I'm not very good at math(in fact, I suck) But I'm confident the answer is 4.
Click to expand...

Uh, no?

I know it can't be 4, because they don't define x in my textbook.

Well, technically it COULD be 4, but I highly doubt it.
 
I'm not sure what how you could possibly simplify it to
Code: 
4x^(2/3) * 5x^-(1/2) = 20x^-(1/3)

you can simplify the 4 and 5 into a 20, but 2/3 and -(1/2) simplifying into 1/3? Doubt you can mess with exponents like that unless the coefficients are equal.

By deduction, the second equation is probably right.


EDIT - Also realize that fractional exponents are just roots in disguise. 4^(2/3) would be sqrt(4)^2 CUBED.
 
well its not like i actually read it. I glanced at long ass math problem, answer was usually involving pemdas, which probably still applies to some point D:
 
Pesmerga said:
I'm not sure what how you could possibly simplify it to
Code: 
4x^(2/3) * 5x^-(1/2) = 20x^-(1/3)

you can simplify the 4 and 5 into a 20, but 2/3 and -(1/2) simplifying into 1/3? Doubt you can mess with exponents like that unless the coefficients are equal.

By deduction, the second equation is probably right.


EDIT - Also realize that fractional exponents are just roots in disguise. 4^(2/3) would be sqrt(4)^2 CUBED.
Click to expand...

Sorry, my mistake. I was combining them as if they were divisors (as i've said, mafs, not my strong point).

Yeah, I know they're just roots, but i'm not supposed to simplify them into roots, lest the problem be decidedly incorrect :p.
 
Substitute any old number in for x and work it out. Shouldn't be too hard. That's what I'd do in that situation. I'm afraid to say I'm not astounding at maths though.
 
Um... I'm not sure what you're asking.

You said, does the first = the second?

I got your equation (with a quick calculation) to be: (4/5) * x^(1/6)
[Four fifths x to the one sixth]

Unless you're asking to find x... which you weren't...

Algebra's fun :D
 
Yeah, sorry, didn't quite understand the second one. But yeah, you need to take the 5 to the power of -1 as well.

And then you can simplify it into the one I gave you.

Edit: Just read your sig there... *creeps out*
 
I think I just remembered why I hate math. \=
 
Druckles said:
Psht, does no-one here like Maths??
Click to expand...

I did until I got to Junior year, then the teacher turned me off it forever, since he would never help me, and if I had a question, he'd respond with, "what NOW?" then barrage me with insults..
 
Can you put an image up? I can't decipher what you're asking.
 
I just took an Algebra final that was 40% of my grade today. :D

Put up an image, I can't read it well either.
 
Maths are only fun when you know whats going on that day. Otherwise, too much :|

Such as me and integration, or finding certain limits...
 
sinkoman said:
Please please please don't mock me for asking for help in Algebra Two. Math isn't my strong point (yeah, everybody says that), and I can't find any help online with this.

Does (4x^(2/3))/(5x^(1/2)) = 4x^(2/3) * 5x^-(1/2) = 20x^-(1/3)

or...

(4x^(2/3))/(5x^(1/2)) = 4x^(2/3) * 5^-1 * x^-(1/2)
Click to expand...
The 5 will not be "flipped" with the x^(1/2). Also (2/3)-(1/2) is not (1/3). The answer should be (4/5)x^(1/6)
he'd respond with, "what NOW?" then barrage me with insults..
Click to expand...
They only get meaner in college. :p
 
sinkoman said:
Please please please don't mock me for asking for help in Algebra Two. Math isn't my strong point (yeah, everybody says that), and I can't find any help online with this.

Does (4x^(2/3))/(5x^(1/2)) = 4x^(2/3) * 5x^-(1/2) = 20x^-(1/3)

or...

(4x^(2/3))/(5x^(1/2)) = 4x^(2/3) * 5^-1 * x^-(1/2)
Click to expand...

The second one is true, the first one isn't.
 
BODMAS, it sounds funnier

Brackets
powers Of
Division
Multiplication
Addition
Subtraction
 
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