bbson john
Tank
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- Feb 11, 2006
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Consider the continuous sinx/x
Take limit x>0
lim (sinx/x) = (lim sinx) / (lim x)
L.H.S. by L'Hospital rule,
R.H.S. by assumption 0/0 = 1
lim (cosx)/(1) = 0/0
1 = 0
cool, baby.
Take limit x>0
lim (sinx/x) = (lim sinx) / (lim x)
L.H.S. by L'Hospital rule,
R.H.S. by assumption 0/0 = 1
lim (cosx)/(1) = 0/0
1 = 0
cool, baby.